本文共 784 字,大约阅读时间需要 2 分钟。
#includeusing namespace std;typedef long long ll;const int N = 1e6 + 10;int n, res, K;int a[N], b[N];void merge(int l, int r) { if (l >= r) return; int mid = l + r >> 1; merge(l, mid); merge(mid + 1, r); int i = l, j = mid + 1, k = l; while (i <= mid && j <= r) { if (a[i] <= a[j]) { b[k++] = a[i++]; } else { b[k++] = a[j++]; res += mid - i + 1;//统计答案 } while (i <= mid)b[k++] = a[i++]; while (j <= r)b[k++] = a[j++]; for (int i = l; i <= r; i++) { a[i] = b[i]; } }}int main() { ios::sync_with_stdio(0); cin >> n; for (int i = 1; i <= n; ++i) { cin >> a[i]; } merge(1, n); cout << res << endl; return 0;}
转载地址:http://cjet.baihongyu.com/